2[n-(4n+22)+10]=2(n+12)

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Solution for 2[n-(4n+22)+10]=2(n+12) equation:


Simplifying
2[n + -1(4n + 22) + 10] = 2(n + 12)

Reorder the terms:
2[n + -1(22 + 4n) + 10] = 2(n + 12)
2[n + (22 * -1 + 4n * -1) + 10] = 2(n + 12)
2[n + (-22 + -4n) + 10] = 2(n + 12)

Reorder the terms:
2[-22 + 10 + n + -4n] = 2(n + 12)

Combine like terms: -22 + 10 = -12
2[-12 + n + -4n] = 2(n + 12)

Combine like terms: n + -4n = -3n
2[-12 + -3n] = 2(n + 12)
[-12 * 2 + -3n * 2] = 2(n + 12)
[-24 + -6n] = 2(n + 12)

Reorder the terms:
-24 + -6n = 2(12 + n)
-24 + -6n = (12 * 2 + n * 2)
-24 + -6n = (24 + 2n)

Solving
-24 + -6n = 24 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-24 + -6n + -2n = 24 + 2n + -2n

Combine like terms: -6n + -2n = -8n
-24 + -8n = 24 + 2n + -2n

Combine like terms: 2n + -2n = 0
-24 + -8n = 24 + 0
-24 + -8n = 24

Add '24' to each side of the equation.
-24 + 24 + -8n = 24 + 24

Combine like terms: -24 + 24 = 0
0 + -8n = 24 + 24
-8n = 24 + 24

Combine like terms: 24 + 24 = 48
-8n = 48

Divide each side by '-8'.
n = -6

Simplifying
n = -6

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